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1.1x^2-0.04-0.4x=0
a = 1.1; b = -0.4; c = -0.04;
Δ = b2-4ac
Δ = -0.42-4·1.1·(-0.04)
Δ = 0.336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.4)-\sqrt{0.336}}{2*1.1}=\frac{0.4-\sqrt{0.336}}{2.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.4)+\sqrt{0.336}}{2*1.1}=\frac{0.4+\sqrt{0.336}}{2.2} $
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